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Thermodynamics & fluid mechanics

Heat transfer fundamentals: conduction, convection and radiation

The three ways heat moves, the formula for each, and how thermal resistances add up through a wall, with a step-by-step insulated wall problem and a radiation example.

On this page
  1. Conduction
  2. Convection
  3. Radiation
  4. Thermal resistance: adding up a wall
  5. Assumptions
  6. Where it matters in design

Thermodynamics tells you how much heat must move; heat transfer tells you how fast it moves and what temperatures result. It decides the size of a heat sink, the thickness of insulation on an oven, whether a motor overheats and how hot an exhaust manifold’s surface gets. Heat moves in three ways: conduction, convection and radiation.

SteelInsulationT hot gasT cold airConvectionmoving gas brings heatto the surface: hA(ΔT)Convectionto the outside airConduction: kA(ΔT)/L
Heat passes from hot gas to cold air through a steel plate and a layer of insulation. Convection carries it to and from the surfaces, and conduction carries it through the layers. The temperature drops most where the resistance is highest: across the insulation.

Conduction

Heat flows through a solid (or a still fluid) from hot to cold, passed from molecule to molecule. Fourier’s law gives the rate through a flat wall:

Q˙=k A (T1−T2)L\dot Q = \frac{k\,A\,(T_1 - T_2)}{L}
SymbolMeaningUnit
Q˙\dot QHeat flow rateW
kkThermal conductivity of the materialW/m·K
AAArea the heat flows throughm²
T1−T2T_1 - T_2Temperature difference across the wallK
LLWall thicknessm
Materialk (W/m·K, approx.)
Copper400
Aluminium200–240
Carbon steel50
Stainless steel15
Glass1
Water0.6
Wood0.1–0.2
Mineral wool insulation0.04
Still air0.026

Convection

Heat is carried between a surface and a moving fluid. Natural convection happens when warm fluid rises by itself; forced convection uses a fan or pump. Newton’s law of cooling gives the rate:

Q˙=h A (Ts−T∞)\dot Q = h\,A\,(T_s - T_\infty)
SymbolMeaningUnit
hhConvection heat transfer coefficientW/m²·K
TsT_sSurface temperatureK
T∞T_\inftyFluid temperature away from the surfaceK

The coefficient hh depends on the fluid, its speed and the geometry, and it is found from experiments and correlations.

Situationh (W/m²·K, typical range)
Natural convection, gases2–25
Forced convection, gases25–250
Natural convection, liquids50–1000
Forced convection, liquids100–20 000
Boiling and condensation2500–100 000

Radiation

Every surface above absolute zero gives off electromagnetic radiation, and it needs no medium: it crosses a vacuum. The net exchange between a small surface and large surroundings is:

Q˙=ε σ A (Ts4−Tsur4)\dot Q = \varepsilon\,\sigma\,A\,(T_s^4 - T_{sur}^4)

where ε\varepsilon is the surface emissivity (0 to 1: about 0.05 for polished aluminium, 0.8–0.95 for painted or oxidised surfaces), σ=5.67×10−8\sigma = 5.67 \times 10^{-8} W/m²·K⁴ is the Stefan–Boltzmann constant, and the temperatures are absolute. Because of the fourth power, radiation dominates at high temperatures: in furnaces, around exhausts and near flames.

Thermal resistance: adding up a wall

Heat flowing through layers in series behaves like current through resistors in series. Each layer and each surface has a resistance, and they simply add:

Rcond=Lk A,Rconv=1h A,Q˙=Thot−Tcold∑RR_{cond} = \frac{L}{k\,A}, \qquad R_{conv} = \frac{1}{h\,A}, \qquad \dot Q = \frac{T_{hot} - T_{cold}}{\sum R}

The layer with the largest resistance takes most of the temperature drop, which is exactly what insulation is for.

Assumptions

  • Steady state: temperatures don’t change with time.
  • One-dimensional heat flow through a flat wall, with no heat generated inside it.
  • Constant thermal conductivity and constant convection coefficients.
  • Radiation ignored in the wall problem below (it would add a parallel path at the hot surface).

Solved problem: an insulated oven wall

An oven wall is 5 mm steel (k = 50 W/m·K) with 50 mm of mineral wool outside it (k = 0.04 W/m·K). The gas inside is at 300 °C with h = 20 W/m²·K; the room is at 25 °C with h = 10 W/m²·K. Find the heat loss per square metre and the temperature of the outer surface. Then compare with no insulation.

Step 1: resistances for 1 m² of wall.

Rin=120=0.050,Rsteel=0.00550=0.0001,Rins=0.050.04=1.25,Rout=110=0.100R_{in} = \frac{1}{20} = 0.050, \quad R_{steel} = \frac{0.005}{50} = 0.0001, \quad R_{ins} = \frac{0.05}{0.04} = 1.25, \quad R_{out} = \frac{1}{10} = 0.100

(all in K/W for 1 m²)

Step 2: total resistance and heat flow.

∑R=1.400 K/W,Q˙=300−251.400=196 W\sum R = 1.400\ \text{K/W}, \qquad \dot Q = \frac{300 - 25}{1.400} = 196\ \text{W}

Step 3: outer surface temperature. The heat crosses the outer air film:

Ts,out=25+196×0.100=44.6 ∘CT_{s,out} = 25 + 196 \times 0.100 = 44.6\ ^\circ\text{C}

Step 4: without insulation.

∑R=0.050+0.0001+0.100=0.150,Q˙=2750.150=1830 W,Ts,out=25+1830×0.1=208 ∘C\sum R = 0.050 + 0.0001 + 0.100 = 0.150, \qquad \dot Q = \frac{275}{0.150} = 1830\ \text{W}, \qquad T_{s,out} = 25 + 1830 \times 0.1 = 208\ ^\circ\text{C}
AnswerWith insulation: 196 W/m² and a 45 °C outer surface. Without it: about 1830 W/m² and over 200 °C, hot enough to burn

The insulation carries almost 90 % of the total resistance, so it takes almost all the temperature drop. The steel layer is so conductive that it hardly matters.

Solved problem: radiation from a hot plate

A painted steel plate of 0.5 m² (ε = 0.8) is at 200 °C in a large room at 25 °C. Find the heat it loses by radiation.

Step 1: absolute temperatures. T_s = 473.15 K, T_sur = 298.15 K.

Step 2: apply the Stefan–Boltzmann law.

Q˙=0.8×5.67×10−8×0.5×(473.154−298.154)=958 W\dot Q = 0.8 \times 5.67 \times 10^{-8} \times 0.5 \times (473.15^4 - 298.15^4) = 958\ \text{W}
AnswerAbout 960 W by radiation alone; natural convection adds a similar amount

Where it matters in design

  • Cooling: fins increase the area A to raise heat loss from motors, electronics and engine cylinders; a fan raises h.
  • Insulation: low-k materials add a large resistance in ovens, cold rooms and exhaust heat shields.
  • Thermal stress: uneven temperatures cause uneven expansion and stress, especially in castings and welded parts that heat up quickly.
  • Material choice: aluminium spreads heat well for heat sinks; stainless steel conducts poorly, which is useful in handles and thermal breaks.

Key points

  • Conduction: kAΔT/L. Convection: hAΔT. Radiation: εσA(T⁴ − T⁴), with absolute temperatures.
  • Resistances in series add up; the largest resistance takes most of the temperature drop.
  • Radiation grows with the fourth power of temperature and matters most for hot surfaces.
  • Raise heat loss with area (fins) and h (fans); reduce it with low-k insulation.

In practice

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