On this page
Fluids are in almost every machine: oil in a hydraulic cylinder, coolant in an engine, air over a car. These ten formulas cover pressure, flow and losses, the quantities you need to size a cylinder, a pump or a duct. Water is taken as ρ = 1000 kg/m³ and air as ρ = 1.2 kg/m³, with g = 9.81 m/s².
1. Hydrostatic pressure
| Symbol | Meaning | SI unit |
|---|---|---|
| Gauge pressure at depth | Pa | |
| Fluid density | kg/m³ | |
| Gravitational acceleration | m/s² | |
| Depth below the free surface | m |
Assumptions: the fluid is at rest and incompressible. Add atmospheric pressure (101.3 kPa) for absolute pressure.
Worked example
Find the gauge pressure 10 m below the surface of a water tank.
2. Pascal’s law and the hydraulic press
| Symbol | Meaning | SI unit |
|---|---|---|
| Forces on the small and large pistons | N | |
| Piston areas | m² |
Assumptions: a confined fluid at rest, pistons at the same height, no friction or leakage. The force is multiplied but the large piston moves less: .
Worked example
A hydraulic press has a 20 mm diameter input piston and a 200 mm diameter output piston. The operator pushes with 200 N.
3. Buoyancy (Archimedes’ principle)
| Symbol | Meaning | SI unit |
|---|---|---|
| Upward buoyant force | N | |
| Density of the fluid | kg/m³ | |
| Submerged volume of the body | m³ |
Assumptions: fluid at rest with uniform density. A body floats when the buoyant force equals its weight before it is fully submerged.
Worked example
An aluminium block (ρ = 2700 kg/m³) of 2 litres is hung under water. Find the buoyant force and its apparent weight.
4. Continuity equation
| Symbol | Meaning | SI unit |
|---|---|---|
| Volume flow rate | m³/s | |
| Flow area | m² | |
| Average velocity | m/s |
Assumptions: steady flow of an incompressible fluid with no leaks. For gases with large density changes use .
Worked example
Water flows at 2 m/s in a 100 mm bore that narrows to 50 mm.
5. Bernoulli’s equation
| Symbol | Meaning | SI unit |
|---|---|---|
| Static pressure | Pa | |
| Density | kg/m³ | |
| Velocity | m/s | |
| Height above a datum | m |
Assumptions: steady, incompressible, frictionless flow along a streamline, with no pump or turbine between the two points. Real flow loses some pressure to friction; add a head loss term to the right-hand side.
Worked example
In the reducer from example 4, the pressure upstream is 200 kPa and the pipe is horizontal. Find the pressure in the 50 mm section.
A full walk-through with a diagram is in Bernoulli’s equation explained with a solved numerical.
6. Reynolds number
| Symbol | Meaning | SI unit |
|---|---|---|
| Reynolds number | none | |
| Average velocity | m/s | |
| Inside diameter (or hydraulic diameter) | m | |
| Dynamic viscosity | Pa·s | |
| Kinematic viscosity, | m²/s |
Assumptions: the limits below are for flow in a round, full bore. Below about 2300 the flow is laminar; above about 4000 it is turbulent; in between it can be either.
Worked example
Water at 20 °C (μ = 1.0 × 10⁻³ Pa·s) flows at 2 m/s in a 100 mm bore.
7. Friction loss (Darcy–Weisbach)
| Symbol | Meaning | SI unit |
|---|---|---|
| Head lost to friction | m | |
| Darcy friction factor | none | |
| Length | m | |
| Inside diameter | m | |
| Average velocity | m/s |
Assumptions: fully developed flow in a straight, round, full bore. For turbulent flow, comes from the Moody chart or the Colebrook equation; it depends on Re and wall roughness. Bends and valves add further losses.
Worked example
Water flows at 2 m/s through 50 m of 100 mm bore with f = 0.02.
8. Laminar friction factor
| Symbol | Meaning | SI unit |
|---|---|---|
| Darcy friction factor | none | |
| Dynamic viscosity | Pa·s | |
| , | Length and diameter | m |
| Average velocity | m/s |
Assumptions: laminar flow (Re below about 2300) of a Newtonian fluid in a round bore. This is the Hagen–Poiseuille result; it is exact for laminar flow and does not depend on roughness.
Worked example
Oil (ρ = 900 kg/m³, μ = 0.1 Pa·s) flows at 0.5 m/s through a 20 mm bore, 10 m long.
9. Pump power
| Symbol | Meaning | SI unit |
|---|---|---|
| Shaft power needed | W | |
| Flow rate | m³/s | |
| Total head the pump adds (lift plus losses) | m | |
| Pump efficiency | none |
Assumptions: steady flow of an incompressible liquid. alone is the hydraulic power given to the fluid.
Worked example
A pump delivers 10 L/s of water against a total head of 30 m at 70 % efficiency.
10. Drag force
| Symbol | Meaning | SI unit |
|---|---|---|
| Drag force | N | |
| Fluid density | kg/m³ | |
| Speed relative to the fluid | m/s | |
| Drag coefficient (from tests or tables) | none | |
| Reference area, usually frontal area | m² |
Assumptions: is roughly constant over the speed range, which holds for bluff bodies at high Reynolds number. The power to overcome drag is , so it rises with the cube of speed.
Worked example
A car with a frontal area of 2.2 m² and C_D = 0.30 drives at 100 km/h (27.8 m/s).
Key points
- Continuity and Bernoulli together explain most flow problems: where the area falls, speed rises and pressure drops.
- Check the Reynolds number first; laminar and turbulent flow need different friction factors.
- Pressure losses grow with the square of velocity, so a slightly larger bore can save a lot of pump power.
- Drag force grows with the square of speed and drag power with the cube.